【Spring Boot】SELECTで関連テーブルの値を取得したい【JPA】

import java.io.Serializable;
import java.util.ArrayList;
import java.util.List;

import jakarta.persistence.CascadeType;
import jakarta.persistence.Column;
import jakarta.persistence.Entity;
import jakarta.persistence.FetchType;
import jakarta.persistence.Id;
import jakarta.persistence.JoinColumn;
import jakarta.persistence.NamedQuery;
import jakarta.persistence.OneToMany;


/**
 * The persistent class for the room database table.
 * 
 */
@Entity
@NamedQuery(name="Room.findAll", query="SELECT r FROM Room r")
public class Room implements Serializable {
	private static final long serialVersionUID = 1L;

	@Id
	private int id;

	private String als;

	@Column(name="room_name")
	private String roomName;

	private String unqals;
	
	@OneToMany(fetch = FetchType.EAGER, cascade= CascadeType.ALL)
  @JoinColumn(name = "room_id")
	private List<Equipment> equipments = new ArrayList<>();
  //以下省略
}

package com.example.demo.entity;

import java.io.Serializable;
import java.util.ArrayList;
import java.util.List;

import org.hibernate.annotations.NamedQuery;

import jakarta.persistence.Column;
import jakarta.persistence.Entity;
import jakarta.persistence.Id;
import jakarta.persistence.OneToMany;


/**
 * The persistent class for the equipment database table.
 * 
 */
@Entity
@NamedQuery(name="Equipment.findAll", query="SELECT e FROM Equipment e")
public class Equipment implements Serializable {
	private static final long serialVersionUID = 1L;

	@Id
	private int id;

	@Column(name="equipment_name")
	private String equipmentName;

	@Column(name="room_id")
	private int roomId;
	
	@OneToMany(mappedBy = "equipment")
 	private List<Test> tests = new ArrayList<>();


	public Equipment() {
	}
// 以下省略
}